如何在Android上通过电源按钮自动启动app页面

public class BootReceiver extends BroadcastReceiver {
    @Override
    public void onReceive(Context context, Intent intent) {
        if (intent.getAction().equals(Intent.ACTION_BOOT_COMPLETED)) {
            // 启动指定的app页面
            Intent launchIntent = new Intent(context, YourAppActivity.class);
            launchIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
            context.startActivity(launchIntent);
        }
    }
}

<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />

<application>
    <receiver
        android:name=".BootReceiver"
        android:enabled="true"
        android:exported="true">
        <intent-filter>
            <action android:name="android.intent.action.BOOT_COMPLETED" />
        </intent-filter>
    </receiver>
</application>

public class YourAppActivity extends AppCompatActivity {
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        
        // 判断是否是从系统启动时直接打开app
        if ((getIntent().getFlags() & Intent.FLAG_ACTIVITY_BROUGHT_TO_FRONT) != 0) {
            // 如果是，则关闭当前页面，保持app的单实例模式
            finish();
            return;
        }
        
        // 正常的页面初始化逻辑
        setContentView(R.layout.activity_main);
        // ...
    }
}