如何在Combine中对任意数量的Bool Publisher执行"all“操作？

import Combine

// 创建一些Bool类型的Publisher
let publisher1 = PassthroughSubject<Bool, Never>()
let publisher2 = PassthroughSubject<Bool, Never>()
let publisher3 = PassthroughSubject<Bool, Never>()

// 将这些Publisher组合起来，并执行"all"操作
let allTruePublisher = Publishers.CombineLatest3(publisher1, publisher2, publisher3)
    .reduce((true, true, true)) { (previousValues, newValues) -> (Bool, Bool, Bool) in
        let (prev1, prev2, prev3) = previousValues
        let (new1, new2, new3) = newValues
        return (prev1 && new1, prev2 && new2, prev3 && new3)
    }
    .map { $0.0 && $0.1 && $0.2 }

// 订阅结果
let cancellable = allTruePublisher.sink { result in
    print("All publishers are true: \(result)")
}

// 发布一些值来测试
publisher1.send(true)
publisher2.send(true)
publisher3.send(false) // 这里会输出false，因为有一个是false