如何在Java中有效地使用SAXParseException

import org.xml.sax.SAXParseException;
import org.xml.sax.helpers.DefaultHandler;

public class MySAXHandler extends DefaultHandler {
    @Override
    public void error(SAXParseException e) {
        System.out.println("Error: " + e.getMessage());
        System.out.println("Line: " + e.getLineNumber());
        System.out.println("Column: " + e.getColumnNumber());
    }

    @Override
    public void fatalError(SAXParseException e) {
        System.out.println("Fatal Error: " + e.getMessage());
        System.out.println("Line: " + e.getLineNumber());
        System.out.println("Column: " + e.getColumnNumber());
    }
}

import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.SAXException;

public class Main {
    public static void main(String[] args) {
        try {
            SAXParserFactory factory = SAXParserFactory.newInstance();
            SAXParser parser = factory.newSAXParser();
            parser.parse("example.xml", new MySAXHandler());
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}