如何在Java语言中用xPath正确解析这个XML文件？

import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathFactory;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathConstants;

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse("path/to/xml/file.xml");

XPathFactory xPathFactory = XPathFactory.newInstance();
XPath xPath = xPathFactory.newXPath();

String expression = "//node"; // 这里的表达式可以根据具体需求进行修改

XPathExpression xPathExpression = xPath.compile(expression);

Object result = xPathExpression.evaluate(document, XPathConstants.NODESET);
NodeList nodeList = (NodeList) result;

for (int i = 0; i < nodeList.getLength(); i++) {
    // 处理每个节点的逻辑
    // 例如，获取节点的文本内容：
    String textContent = nodeList.item(i).getTextContent();
    // 或者，获取节点的属性值：
    String attributeValue = nodeList.item(i).getAttributes().getNamedItem("attributeName").getNodeValue();
}