如何在Python中使用SWIG将operator<<封装为__str__？

#include <iostream>
#include <string>

class Example {
public:
    Example(const std::string& name) : name(name) {}

    friend std::ostream& operator<<(std::ostream& os, const Example& example) {
        os << "Example: " << example.name;
        return os;
    }

private:
    std::string name;
};

%module example

%{
#include "example.cpp"
%}

%include <std_string.i>
%include <std_ostream.i>

%{
#include "example.cpp"
%}

%extend Example {
    std::ostream& operator<<(std::ostream& os) {
        return operator<<(os, *$self);
    }
}

swig -python example.i

cmake_minimum_required(VERSION 3.12)
project(example)

find_package(PythonLibs REQUIRED)
include_directories(${PYTHON_INCLUDE_DIRS})

add_library(_example SHARED example_wrap.cxx)
target_link_libraries(_example ${PYTHON_LIBRARIES})

cmake .
make

import example

e = example.Example("Test")
print(str(e))