如何在Python中对列表进行快速排序，使其对应的索引具有相似的时间戳？

def quick_sort(lst):
    if len(lst) <= 1:
        return lst
    pivot = lst[len(lst) // 2]
    left = [x for x in lst if x < pivot]
    middle = [x for x in lst if x == pivot]
    right = [x for x in lst if x > pivot]
    return quick_sort(left) + middle + quick_sort(right)

# 示例使用
my_list = [5, 2, 9, 1, 7]
sorted_list = quick_sort(my_list)
print(sorted_list)

def quick_sort_with_timestamp(lst):
    if len(lst) <= 1:
        return [(i, x) for i, x in enumerate(lst)]
    pivot = lst[len(lst) // 2]
    left = [x for x in lst if x[1] < pivot[1]]
    middle = [x for x in lst if x[1] == pivot[1]]
    right = [x for x in lst if x[1] > pivot[1]]
    return quick_sort_with_timestamp(left) + middle + quick_sort_with_timestamp(right)

# 示例使用
my_list = [(0, 5), (1, 2), (2, 9), (3, 1), (4, 7)]
sorted_list = quick_sort_with_timestamp(my_list)
print(sorted_list)