如何在Spring MVC中为简单表继承域创建控制器？

// 实体类
@Entity
@Table(name = "simple_table")
public class SimpleTable {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    private String name;

    // 省略其他属性和方法
}

// 数据访问层接口
public interface SimpleTableDao {
    void save(SimpleTable simpleTable);

    List<SimpleTable> getAll();
}

// 数据访问层实现类
@Repository
public class SimpleTableDaoImpl implements SimpleTableDao {
    @Autowired
    private JdbcTemplate jdbcTemplate;

    @Override
    public void save(SimpleTable simpleTable) {
        String sql = "INSERT INTO simple_table (name) VALUES (?)";
        jdbcTemplate.update(sql, simpleTable.getName());
    }

    @Override
    public List<SimpleTable> getAll() {
        String sql = "SELECT * FROM simple_table";
        return jdbcTemplate.query(sql, new BeanPropertyRowMapper<>(SimpleTable.class));
    }
}

// 服务层接口
public interface SimpleTableService {
    void save(SimpleTable simpleTable);

    List<SimpleTable> getAll();
}

// 服务层实现类
@Service
public class SimpleTableServiceImpl implements SimpleTableService {
    @Autowired
    private SimpleTableDao simpleTableDao;

    @Override
    public void save(SimpleTable simpleTable) {
        simpleTableDao.save(simpleTable);
    }

    @Override
    public List<SimpleTable> getAll() {
        return simpleTableDao.getAll();
    }
}

// 控制器类
@Controller
@RequestMapping("/simple-table")
public class SimpleTableController {
    @Autowired
    private SimpleTableService simpleTableService;

    @PostMapping("/save")
    public String save(@ModelAttribute SimpleTable simpleTable) {
        simpleTableService.save(simpleTable);
        return "redirect:/simple-table/list";
    }

    @GetMapping("/list")
    public String list(Model model) {
        List<SimpleTable> simpleTables = simpleTableService.getAll();
        model.addAttribute("simpleTables", simpleTables);
        return "simple-table-list";
    }
}