如何在ThreadPoolExecutor中实现submit方法吞噬异常，但执行-not

import java.util.concurrent.*;

public class ExceptionSwallowingTask<V> extends FutureTask<V> {
    public ExceptionSwallowingTask(Callable<V> callable) {
        super(callable);
    }

    @Override
    protected void done() {
        try {
            get();
        } catch (InterruptedException e) {
            Thread.currentThread().interrupt();
        } catch (ExecutionException e) {
            // 异常处理逻辑，可以根据具体需求进行处理
            System.err.println("任务执行过程中发生异常：" + e.getCause());
        }
    }
}

public class Main {
    public static void main(String[] args) {
        ThreadPoolExecutor executor = new ThreadPoolExecutor(
                10, 10, 0, TimeUnit.SECONDS,
                new LinkedBlockingQueue<>()
        );

        Callable<Integer> task = () -> {
            // 模拟任务执行过程中抛出异常
            throw new RuntimeException("任务执行异常");
        };

        // 使用自定义的任务类
        Future<Integer> future = executor.submit(new ExceptionSwallowingTask<>(task));

        try {
            // 获取任务执行结果，不会抛出异常
            Integer result = future.get();
            System.out.println("任务执行结果：" + result);
        } catch (InterruptedException | ExecutionException e) {
            e.printStackTrace();
        }

        executor.shutdown();
    }
}