新来的紫芝眉宇,参加过亚洲区域赛晋级 It's Saturday today, what day is it after11 + 22 + 33 + ... + NN days? Input The
A Short problem Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1716 Accepted Submission(s): 631 Problem Description According to a research, VIM users tend to have shorter fingers, compared
async 与 await 的使用方式相对简单。 当你尝试在循环中使用await时,事情就会变得复杂一些。
你想从fruitBasket获得每个水果的数量。 要获取水果的数量,可以使用getNumFruit函数。
Function Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others) Total
Milking Grid Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 6169 Accepted: 2573 Description Every morning when they are milked, the Farmer John's cows form a rectangular grid that is R (1 <= R <= 10,000) rows by C (1 <= C <= 75) c
最近想学习Libra数字货币的MOVE语言,发现它是用Rust编写的,所以先补一下Rust的基础知识。学习了一段时间,发现Rust的学习曲线非常陡峭,不过仍有快速入门的办法。
POJ 2406 Power Strings http://poj.org/problem?id=2406 题意:找出s字符窜由多少个重复子窜循环构成 分析:KMP求出next数组,其i-next[i
"Let it Bead" company is located upstairs at 700 Cannery Row in Monterey, CA. As you can deduce from the company name, their business is beads. Their PR department found out that customers are interested in buying colored bracelets. However, over 90 percent of the target audience insists that the bracelets be unique. (Just imagine what happened if two women showed up at the same party wearing identical bracelets!) It's a good thing that bracelets can have different lengths and need not be made of beads of one color. Help the boss estimating maximum profit by calculating how many different bracelets can be produced. A bracelet is a ring-like sequence of s beads each of which can have one of c distinct colors. The ring is closed, i.e. has no beginning or end, and has no direction. Assume an unlimited supply of beads of each color. For different values of s and c, calculate the number of different bracelets that can be made.
例6 题目链接:POJ2752 这道题目的大意是给定一个字符串S,让找出所有既是S前缀又是S后缀的字符串。然后从小到大输出它们的长度 比如S=ababcababababcabab,既是前缀
Give you a string with length N, you can generate N strings by left shifts. For example let consider the string “SKYLONG”, we can generate seven strings: String Rank SKYLONG 1 KYLONGS 2 YLONGSK 3 LONGSKY 4 ONGSKYL 5 NGSKYLO 6 GSKYLON 7 and lexicographically first of them is GSKYLON, lexicographically last is YLONGSK, both of them appear only once. Your task is easy, calculate the lexicographically fisrt string’s Rank (if there are multiple answers, choose the smallest one), its times, lexicographically last string’s Rank (if there are multiple answers, choose the smallest one), and its times also.
本文翻译至Nolan Lawson的一篇博客——《We have a problem with promises》 关于Promise 大家通常认为Promise是ES6提供的一个书写异步代码的解决方案,他的主要贡献是解决了“回调地狱”,但其实Promise更多的是提供了一种代码结构和流程控制机制。所以很多新手刚开始学习和使用Promise时,如果思路不能转换过来的话,经常会出现一些本末倒置的错误。 希望通过列举出下面新手的错误让大家能巩固一下关于Promise的基础知识 新手错误列举 #1 回调地狱版Pr
小春现在很清闲,面对书桌上的N张牌,他决定给每张染色,目前小春只有3种颜色:红色,蓝色,绿色.他询问Sun有 多少种染色方案,Sun很快就给出了答案.进一步,小春要求染出Sr张红色,Sb张蓝色,Sg张绝色.他又询问有多少种方 案,Sun想了一下,又给出了正确答案. 最后小春发明了M种不同的洗牌法,这里他又问Sun有多少种不同的染色方案. 两种染色方法相同当且仅当其中一种可以通过任意的洗牌法(即可以使用多种洗牌法,而每种方法可以使用多次)洗 成另一种.Sun发现这个问题有点难度,决定交给你,答案可能很大,只要求出答案除以P的余数(P为质数).
在 Javascript 循环中使用 async/ await 循环遍历数组似乎很简单,但是在将两者结合使用时需要注意一些非直观的行为。让我们看看三个不同的例子,看看你应该注意什么,以及哪个循环最适合特定用例。
该文章是关于计算字符串的循环节出现的次数以及前缀循环节出现次数的情况。文章使用了动态规划的方法,通过记录字符串中每个字符出现的次数,来计算出循环节和前缀循环节出现次数。同时,对于每个前缀,文章计算了以该前缀开头的所有字符串的循环节出现次数,并记录了出现次数大于1的字符串的前缀。
数据抓取中的密集任务处理,往往会涉及到性能瓶颈,这时候如果能有多进程的工具来进行支持,那么往往效率会提升很多。 今天这一篇分享在R语言、Python中使用调用多进程功能进行二进制文件下载。 导入待下载的文件: library("dplyr") mydata<-read.csv("D:/Python/File/toutiaoreport.csv",stringsAsFactors = FALSE,check.names = FALSE) 抽取报告的url和报告名称: mydata1<-mydata[1:10
Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 175657 Accepted Submission(s): 43409 Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A
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前两天在Cocos官方公众号上学习了「大掌教」的Cocos Creator 2.x Camera教程,总算是对摄像机组件有了一个初步的认识,乘热打铁Shawn用Camera摄像机练习了一个飞机大战游戏,目前主要实现3个功能:
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