如何在json输出中将双精度值转换为字符串

const data = {
  value: 3.141592653589793
};

const jsonString = JSON.stringify(data, (key, value) => {
  if (typeof value === 'number' && !Number.isInteger(value)) {
    return value.toString();
  }
  return value;
});

console.log(jsonString); // 输出: {"value":"3.141592653589793"}

import json

class DoubleToStringEncoder(json.JSONEncoder):
    def default(self, obj):
        if isinstance(obj, float):
            return str(obj)
        return super(DoubleToStringEncoder, self).default(obj)

data = {
    'value': 3.141592653589793
}

json_string = json.dumps(data, cls=DoubleToStringEncoder)
print(json_string)  # 输出: {"value": "3.141592653589793"}

import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.module.SimpleModule;
import com.fasterxml.jackson.databind.ser.std.ToStringSerializer;

public class Main {
    public static void main(String[] args) throws JsonProcessingException {
        ObjectMapper mapper = new ObjectMapper();
        SimpleModule module = new SimpleModule();
        module.addSerializer(Double.class, ToStringSerializer.instance);
        mapper.registerModule(module);

        Data data = new Data();
        data.setValue(3.141592653589793);

        String jsonString = mapper.writeValueAsString(data);
        System.out.println(jsonString);  // 输出: {"value":"3.141592653589793"}
    }
}

class Data {
    private double value;

    public double getValue() {
        return value;
    }

    public void setValue(double value) {
        this.value = value;
    }
}