如何在python中将最多63位的数字转换为word？

def number_to_word(number):
    units = ['', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']
    tens = ['', '', 'twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety']
    teens = ['ten', 'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen']
    groups = [('billion', 1000000000), ('million', 1000000), ('thousand', 1000), ('', 1)]

    if number == 0:
        return 'zero'

    result = ''
    if number < 0:
        result += 'negative '
        number = abs(number)

    for group_name, group_value in groups:
        if number >= group_value:
            group_number = number // group_value
            number %= group_value
            if group_number >= 100:
                result += units[group_number // 100] + ' hundred '
                group_number %= 100

            if group_number >= 20:
                result += tens[group_number // 10] + ' '
                group_number %= 10
            elif group_number >= 10:
                result += teens[group_number - 10] + ' '
                group_number = 0

            if group_number > 0:
                result += units[group_number] + ' '

            if group_name:
                result += group_name + ' '

    return result.strip()

# 示例用法
number = 123456789
word = number_to_word(number)
print(f"The word representation of {number} is: {word}")