如何在react native中同时使用多个状态的过滤功能

import React, { useState } from 'react';
import { View, Text, Button, FlatList } from 'react-native';

const App = () => {
  // 假设有三个状态需要过滤：价格、评分和是否新品
  const [priceFilter, setPriceFilter] = useState('');
  const [ratingFilter, setRatingFilter] = useState('');
  const [isNewFilter, setIsNewFilter] = useState('');

  // 示例数据
  const products = [
    { id: '1', name: 'Product A', price: 100, rating: 4.5, isNew: true },
    { id: '2', name: 'Product B', price: 200, rating: 3.5, isNew: false },
    { id: '3', name: 'Product C', price: 150, rating: 4.0, isNew: true },
    // 更多产品...
  ];

  // 过滤逻辑
  const filteredProducts = products.filter(product => {
    const priceMatch = priceFilter ? product.price <= parseInt(priceFilter) : true;
    const ratingMatch = ratingFilter ? product.rating >= parseFloat(ratingFilter) : true;
    const isNewMatch = isNewFilter === 'true' ? product.isNew : true;
    return priceMatch && ratingMatch && isNewMatch;
  });

  return (
    <View>
      <Text>Price Filter:</Text>
      <Button title="Under 100" onPress={() => setPriceFilter(100)} />
      <Button title="Under 200" onPress={() => setPriceFilter(200)} />

      <Text>Rating Filter:</Text>
      <Button title="4+" onPress={() => setRatingFilter(4)} />
      <Button title="3+" onPress={() => setRatingFilter(3)} />

      <Text>Is New:</Text>
      <Button title="Yes" onPress={() => setIsNewFilter('true')} />
      <Button title="No" onPress={() => setIsNewFilter('false')} />

      <FlatList
        data={filteredProducts}
        keyExtractor={item => item.id}
        renderItem={({ item }) => (
          <View>
            <Text>{item.name} - ${item.price} - Rating: {item.rating} - Is New: {item.isNew ? 'Yes' : 'No'}</Text>
          </View>
        )}
      />
    </View>
  );
};

export default App;