如何在spring data jpa中使用postgres中创建的扩展

@TypeDef(name = "my_extension", typeClass = MyExtensionType.class)
@Entity
public class MyEntity {
    // ...
    @Type(type = "my_extension")
    private MyExtension myExtension;
    // ...
}

public class MyExtensionType implements UserType {
    // 实现必要的方法
    // ...
}

<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <!-- ... -->
    <property name="jpaPropertyMap">
        <map>
            <entry key="hibernate.hbm2ddl.auto" value="update" />
            <entry key="hibernate.dialect" value="org.hibernate.dialect.PostgreSQLDialect" />
            <entry key="hibernate.connection.charSet" value="UTF-8" />
            <entry key="hibernate.type_contributors" value="com.example.MyExtensionTypeContributor" />
        </map>
    </property>
</bean>

public class MyExtensionTypeContributor implements TypeContributor {
    @Override
    public void contribute(TypeContributions typeContributions, ServiceRegistry serviceRegistry) {
        typeContributions.contributeType(new MyExtensionType());
    }
}

@Repository
public interface MyEntityRepository extends JpaRepository<MyEntity, Long> {
    List<MyEntity> findByMyExtension(MyExtension myExtension);
}