如何在swift中获取响应JSON

import Foundation

guard let url = URL(string: "https://example.com/api/data.json") else {
    print("无效的URL")
    return
}

let session = URLSession.shared
let task = session.dataTask(with: url) { (data, response, error) in
    if let error = error {
        print("请求错误：\(error.localizedDescription)")
        return
    }
    
    guard let httpResponse = response as? HTTPURLResponse,
          (200...299).contains(httpResponse.statusCode) else {
        print("无效的响应")
        return
    }
    
    if let data = data {
        // 在这里处理响应数据
        do {
            let json = try JSONSerialization.jsonObject(with: data, options: [])
            // 对JSON进行解析和处理
            print(json)
        } catch {
            print("JSON解析错误：\(error.localizedDescription)")
        }
    }
}

task.resume()