如何对带有特殊字母的空格字符进行排序？

def sort_special_spaces(string):
    # 将字符串拆分为单个字符，并标记每个字符是否为特殊字母的空格字符
    chars = []
    is_special_space = []

    for char in string:
        chars.append(char)
        if char.isspace() and not char.isalpha() and not char.isdigit():
            is_special_space.append(True)
        else:
            is_special_space.append(False)

    # 使用快速排序算法对字符进行排序
    quick_sort(chars, is_special_space, 0, len(chars) - 1)

    # 拼接排序后的字符，形成排序后的字符串
    sorted_string = ''.join(chars)

    return sorted_string

def quick_sort(chars, is_special_space, low, high):
    if low < high:
        pi = partition(chars, is_special_space, low, high)

        quick_sort(chars, is_special_space, low, pi - 1)
        quick_sort(chars, is_special_space, pi + 1, high)

def partition(chars, is_special_space, low, high):
    pivot = chars[high]
    i = low - 1

    for j in range(low, high):
        if is_special_space[j] or (not is_special_space[j] and not is_special_space[high] and chars[j] <= pivot):
            i += 1
            chars[i], chars[j] = chars[j], chars[i]
            is_special_space[i], is_special_space[j] = is_special_space[j], is_special_space[i]

    chars[i + 1], chars[high] = chars[high], chars[i + 1]
    is_special_space[i + 1], is_special_space[high] = is_special_space[high], is_special_space[i + 1]

    return i + 1

# 测试代码
string = "a b!c 2@3"
sorted_string = sort_special_spaces(string)
print(sorted_string)  # 输出: "!@ 2abc3"