如何对整个矩阵进行排序，而不必将其转换为一维数组

# 矩阵排序函数
def sort_matrix(matrix):
    # 行排序
    for row in matrix:
        row.sort()
    
    # 列排序
    transposed_matrix = [[row[i] for row in matrix] for i in range(len(matrix[0]))]
    for row in transposed_matrix:
        row.sort()
    
    # 结果转置回来
    sorted_matrix = [[row[i] for row in transposed_matrix] for i in range(len(transposed_matrix[0]))]
    
    return sorted_matrix

# 示例矩阵
matrix = [[5, 3, 9],
          [2, 8, 7],
          [1, 4, 6]]

# 调用排序函数并打印结果
sorted_matrix = sort_matrix(matrix)
for row in sorted_matrix:
    print(row)