如何将时间字符串(例如"8:02 AM")转换为可排序字段

from datetime import datetime

# 时间字符串
time_str = "8:02 AM"

# 解析时间字符串
time_obj = datetime.strptime(time_str, "%I:%M %p")

# 转换为UNIX时间戳
timestamp = time_obj.timestamp()

print(timestamp)

// 时间字符串
const timeStr = "8:02 AM";

// 解析时间字符串
const timeObj = new Date(`1970-01-01T${timeStr}Z`);

// 转换为UNIX时间戳（毫秒）
const timestamp = timeObj.getTime() / 1000;

console.log(timestamp);

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;

public class TimeConversion {
    public static void main(String[] args) {
        String timeStr = "8:02 AM";
        SimpleDateFormat sdf = new SimpleDateFormat("h:mm a");

        try {
            // 解析时间字符串
            Date timeObj = sdf.parse(timeStr);

            // 转换为UNIX时间戳（毫秒）
            long timestamp = timeObj.getTime() / 1000;

            System.out.println(timestamp);
        } catch (ParseException e) {
            e.printStackTrace();
        }
    }
}