如何将xml转换为xamarin

using System;
using System.Xml;

public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public class XmlToXamarinConverter
{
    public static Person ConvertXmlToPerson(string xml)
    {
        XmlDocument xmlDoc = new XmlDocument();
        xmlDoc.LoadXml(xml);

        XmlNode nameNode = xmlDoc.SelectSingleNode("/Person/Name");
        XmlNode ageNode = xmlDoc.SelectSingleNode("/Person/Age");

        Person person = new Person();
        person.Name = nameNode.InnerText;
        person.Age = Convert.ToInt32(ageNode.InnerText);

        return person;
    }
}

public class Program
{
    public static void Main()
    {
        string xml = "<Person><Name>John Doe</Name><Age>30</Age></Person>";
        Person person = XmlToXamarinConverter.ConvertXmlToPerson(xml);

        Console.WriteLine("Name: " + person.Name);
        Console.WriteLine("Age: " + person.Age);
    }
}