如何找到抛物线的最大或最小y_value对应的x_value？(在Python中)

import math

def find_vertex(a, b, c):
    # 计算顶点的x坐标
    vertex_x = -b / (2 * a)
    # 计算顶点的y坐标
    vertex_y = a * vertex_x**2 + b * vertex_x + c
    return vertex_x, vertex_y

def find_max_or_min(a, b, c):
    # 计算顶点的坐标
    vertex_x, vertex_y = find_vertex(a, b, c)
    # 判断抛物线的开口方向
    if a > 0:
        # 抛物线开口向上，顶点为最小值
        return vertex_x, vertex_y
    else:
        # 抛物线开口向下，顶点为最大值
        return vertex_x, vertex_y

# 示例抛物线方程：y = 2x^2 + 3x + 1
a = 2
b = 3
c = 1

# 找到最小值对应的x值和y值
min_x, min_y = find_max_or_min(a, b, c)
print("最小值对应的x值：", min_x)
print("最小值：", min_y)

# 找到最大值对应的x值和y值
max_x, max_y = find_max_or_min(-a, b, c)
print("最大值对应的x值：", max_x)
print("最大值：", max_y)