如何按时间戳对行进行分组？

import datetime

# 假设数据集中的时间戳列名为"timestamp"，数据存储在一个名为"data"的列表中
data = [
    {"timestamp": "2022-01-01 10:00:00", "value": 1},
    {"timestamp": "2022-01-01 10:05:00", "value": 2},
    {"timestamp": "2022-01-01 11:00:00", "value": 3},
    {"timestamp": "2022-01-02 09:00:00", "value": 4},
    {"timestamp": "2022-01-02 09:30:00", "value": 5},
]

# 按时间戳对行进行分组
grouped_data = {}

for row in data:
    timestamp = datetime.datetime.strptime(row["timestamp"], "%Y-%m-%d %H:%M:%S")
    # 选择按天进行分组
    group_key = timestamp.strftime("%Y-%m-%d")
    
    if group_key not in grouped_data:
        grouped_data[group_key] = []
    
    grouped_data[group_key].append(row)

# 打印分组后的数据
for group_key, rows in grouped_data.items():
    print(f"Group: {group_key}")
    for row in rows:
        print(row)
    print()