如何最好地避免可能的多个枚举，同时又保持异步？

const promise1 = new Promise((resolve, reject) => {
  setTimeout(() => {
    resolve('Promise 1 resolved');
  }, 2000);
});

const promise2 = new Promise((resolve, reject) => {
  setTimeout(() => {
    resolve('Promise 2 resolved');
  }, 3000);
});

const promise3 = new Promise((resolve, reject) => {
  setTimeout(() => {
    resolve('Promise 3 resolved');
  }, 1500);
});

Promise.all([promise1, promise2, promise3])
  .then(results => {
    console.log(results); // ['Promise 1 resolved', 'Promise 2 resolved', 'Promise 3 resolved']
    // 进行后续处理
  })
  .catch(error => {
    console.error(error);
    // 处理错误
  });