如何构建一个异常类来报告C++中的哪些文件和行号？

#include <exception>
#include <string>

class FileLineException : public std::exception {
public:
    FileLineException(const std::string& file, int line) : file_(file), line_(line) {}

    const char* what() const noexcept override {
        return message_.c_str();
    }

    const std::string& getFile() const {
        return file_;
    }

    int getLine() const {
        return line_;
    }

private:
    std::string file_;
    int line_;
    std::string message_ = "Exception occurred at file: " + file_ + ", line: " + std::to_string(line_);
};

void foo() {
    throw FileLineException(__FILE__, __LINE__);
}

int main() {
    try {
        foo();
    } catch (const FileLineException& e) {
        std::cout << "Exception caught at file: " << e.getFile() << ", line: " << e.getLine() << std::endl;
    }

    return 0;
}