如何查找两个目录中具有不同内容的文件名

import os
import hashlib

def get_file_hash(file_path):
    with open(file_path, 'rb') as file:
        content = file.read()
        hash_value = hashlib.sha256(content).hexdigest()
    return hash_value

def find_different_files(dir1, dir2):
    file_dict1 = {}
    file_dict2 = {}

    # 获取目录1中的文件名和哈希值
    for file_name in os.listdir(dir1):
        file_path = os.path.join(dir1, file_name)
        if os.path.isfile(file_path):
            file_dict1[file_name] = get_file_hash(file_path)

    # 获取目录2中的文件名和哈希值
    for file_name in os.listdir(dir2):
        file_path = os.path.join(dir2, file_name)
        if os.path.isfile(file_path):
            file_dict2[file_name] = get_file_hash(file_path)

    different_files = []

    # 比较两个目录中的文件名和哈希值
    for file_name, hash_value in file_dict1.items():
        if file_name in file_dict2:
            if hash_value != file_dict2[file_name]:
                different_files.append(file_name)
        else:
            different_files.append(file_name)

    for file_name in file_dict2.keys():
        if file_name not in file_dict1:
            different_files.append(file_name)

    return different_files

# 示例用法
dir1 = '/path/to/directory1'
dir2 = '/path/to/directory2'
result = find_different_files(dir1, dir2)
print(result)