如何根据列表的长度将包含列表的字典拆分成相等的部分

def split_dict_by_length(dictionary, num_parts):
    dict_length = len(dictionary)
    part_length = dict_length // num_parts
    result = []

    for i, (key, value) in enumerate(dictionary.items()):
        if i >= dict_length - dict_length % num_parts:
            # 最后一个部分
            if not result or len(result[-1]) >= part_length:
                result.append({})
            result[-1][key] = value
        else:
            # 其他部分
            if i % part_length == 0:
                result.append({})
            result[-1][key] = value

    return result

# 示例用法
my_dict = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5, 'f': 6, 'g': 7, 'h': 8, 'i': 9, 'j': 10}
num_parts = 3
result = split_dict_by_length(my_dict, num_parts)
print(result)