如何根据散列中的所有键是否与另一个散列匹配来从数组中删除散列

function removeHashFromArray(array, targetHash) {
  for (var i = array.length - 1; i >= 0; i--) {
    var currentHash = array[i];
    var match = true;
    
    // 检查每个键是否与目标散列匹配
    for (var key in targetHash) {
      if (targetHash.hasOwnProperty(key) && targetHash[key] !== currentHash[key]) {
        match = false;
        break;
      }
    }
    
    // 如果匹配，则从数组中删除散列
    if (match) {
      array.splice(i, 1);
    }
  }
}

// 示例用法
var hashes = [
  { name: 'hash1', value: 1 },
  { name: 'hash2', value: 2 },
  { name: 'hash3', value: 3 },
  { name: 'hash4', value: 4 }
];

var targetHash = { name: 'hash2', value: 2 };

removeHashFromArray(hashes, targetHash);

console.log(hashes);
// 输出: [{ name: 'hash1', value: 1 }, { name: 'hash3', value: 3 }, { name: 'hash4', value: 4 }]