如何比较两个数组对象(非常嵌套)，如果存在，则返回匹配值

def compare_arrays(arr1, arr2):
    # 如果数组长度不同，则直接返回False
    if len(arr1) != len(arr2):
        return False
    
    # 遍历数组中的每个元素
    for i in range(len(arr1)):
        # 如果元素是字典类型，则递归比较
        if isinstance(arr1[i], dict) and isinstance(arr2[i], dict):
            if not compare_arrays(arr1[i], arr2[i]):
                return False
        # 如果元素是列表类型，则递归比较
        elif isinstance(arr1[i], list) and isinstance(arr2[i], list):
            if not compare_arrays(arr1[i], arr2[i]):
                return False
        # 其他情况下直接比较元素值
        elif arr1[i] != arr2[i]:
            return False
    
    # 所有元素比较完毕，返回True
    return True

arr1 = [
    {
        "name": "Alice",
        "age": 25,
        "hobbies": ["reading", "painting"]
    },
    {
        "name": "Bob",
        "age": 30,
        "hobbies": ["music", "sports"]
    }
]

arr2 = [
    {
        "name": "Alice",
        "age": 25,
        "hobbies": ["reading", "painting"]
    },
    {
        "name": "Bob",
        "age": 30,
        "hobbies": ["music", "sports"]
    }
]

if compare_arrays(arr1, arr2):
    print("两个数组对象匹配")
else:
    print("两个数组对象不匹配")