将命令参数与argv []进行比较不起作用

#include<stdio.h>
#include<string.h>

int main(int argc, char *argv[]) {
    if (argc < 2) {
        printf("Usage: %s<argument>\n", argv[0]);
        return 1;
    }

    if (strcmp(argv[1], "arg1") == 0) {
        printf("Argument is 'arg1'\n");
    } else if (strcmp(argv[1], "arg2") == 0) {
        printf("Argument is 'arg2'\n");
    } else {
        printf("Unknown argument: %s\n", argv[1]);
    }

    return 0;
}