将嵌套的有区别的联合表达式转换为字符串

def convert_expression_to_string(expression):
    if isinstance(expression, str):
        return expression
    elif isinstance(expression, dict):
        operator = expression.get('operator')
        operands = expression.get('operands')
        if operator == 'AND':
            return '(' + ' AND '.join([convert_expression_to_string(op) for op in operands]) + ')'
        elif operator == 'OR':
            return '(' + ' OR '.join([convert_expression_to_string(op) for op in operands]) + ')'
        elif operator == 'NOT':
            return 'NOT ' + convert_expression_to_string(operands)
    return ''

# 示例用法
expression = {
    'operator': 'AND',
    'operands': [
        'A',
        {
            'operator': 'OR',
            'operands': ['B', 'C']
        }
    ]
}

result = convert_expression_to_string(expression)
print(result)  # 输出：(A AND (B OR C))