将管道用于多个ifelse函数的问题

result = condition1() | action1() \
         | condition2() | action2() \
         | condition3() | action3() \
         | default_action()

def condition1():
    # 判断条件1是否满足
    if condition1:
        return True
    else:
        return False

def action1():
    # 执行条件1满足时的操作
    pass

def condition2():
    # 判断条件2是否满足
    if condition2:
        return True
    else:
        return False

def action2():
    # 执行条件2满足时的操作
    pass

def condition3():
    # 判断条件3是否满足
    if condition3:
        return True
    else:
        return False

def action3():
    # 执行条件3满足时的操作
    pass

def default_action():
    # 所有条件都不满足时的默认操作
    pass