将项目列表转换为多个字典，其中每个键只有一个列表中的值

def convert_to_dicts(project_list):
    dicts_list = []
    for project in project_list:
        project_dict = {}
        for key, value in project.items():
            if isinstance(value, list):
                for i, item in enumerate(value):
                    project_dict[key + str(i+1)] = item
            else:
                project_dict[key] = value
        dicts_list.append(project_dict)
    return dicts_list

project_list = [
    {"name": "Project A", "languages": ["Python", "Java"], "frameworks": ["Django", "Spring"]},
    {"name": "Project B", "languages": ["JavaScript"], "frameworks": ["React"]},
    {"name": "Project C", "languages": ["C++"], "frameworks": ["Qt"]}
]

dicts_list = convert_to_dicts(project_list)
for project_dict in dicts_list:
    print(project_dict)

{'name': 'Project A', 'languages1': 'Python', 'languages2': 'Java', 'frameworks1': 'Django', 'frameworks2': 'Spring'}
{'name': 'Project B', 'languages1': 'JavaScript', 'frameworks1': 'React'}
{'name': 'Project C', 'languages1': 'C++', 'frameworks1': 'Qt'}