尝试使用在SafariViewController中启动链接的tableviewcell在swift中创建选项卡式应用程序

let tabBarController = UITabBarController()
window?.rootViewController = tabBarController

let viewController1 = ViewController1()
let viewController2 = ViewController2()
let viewController3 = ViewController3()

tabBarController.viewControllers = [viewController1, viewController2, viewController3]

viewController1.tabBarItem = UITabBarItem(title: "Tab 1", image: UIImage(named: "tab1"), selectedImage: UIImage(named: "tab1_selected"))
viewController2.tabBarItem = UITabBarItem(title: "Tab 2", image: UIImage(named: "tab2"), selectedImage: UIImage(named: "tab2_selected"))
viewController3.tabBarItem = UITabBarItem(title: "Tab 3", image: UIImage(named: "tab3"), selectedImage: UIImage(named: "tab3_selected"))

class AppDelegate: UIResponder, UIApplicationDelegate, UITabBarControllerDelegate {
    func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {
        tabBarController.delegate = self
        return true
    }
    
    func tabBarController(_ tabBarController: UITabBarController, didSelect viewController: UIViewController) {
        // 处理选项卡切换事件
    }
}