当只知道文件名时，如何获取文件名的路径？

 def get_file_path(file_name):

     for root, dirs, files in os.walk('/'):

         if file_name in files:

             return os.path.join(root, file_name)

     return None

 file_name = 'example.txt'

 file_path = get_file_path(file_name)

 if file_path:

     print(f"The path of {file_name} is {file_path}")

 else:

     print(f"{file_name} not found")

 ```

 public class FilePathFinder {

     public static String getFilePath(String fileName) {

         File root = new File("/");

         File[] files = root.listFiles();

         if (files != null) {

             for (File file : files) {

                 if (file.getName().equals(fileName)) {

                     return file.getAbsolutePath();

                 }

             }

         }

         return null;

     }

     public static void main(String[] args) {

         String fileName = "example.txt";

         String filePath = getFilePath(fileName);

         if (filePath != null) {

             System.out.println("The path of " + fileName + " is " + filePath);

         } else {

             System.out.println(fileName + " not found");

         }

     }

 }

 ```

 function getFilePath(fileName) {

     const rootDir = '/';

     const files = fs.readdirSync(rootDir);

     for (const file of files) {

         if (file === fileName) {

             return path.join(rootDir, file);

         }

     }

     return null;

 }

 const fileName = 'example.txt';

 const filePath = getFilePath(fileName);

 if (filePath) {

     console.log(`The path of ${fileName} is ${filePath}`);

 } else {

     console.log(`${fileName} not found`);

 }

 ```