当给定要删除的节点的值时，如何从链表中删除该节点

class ListNode:
    def __init__(self, val=0, next=None):
        self.val = val
        self.next = next

def deleteNode(head, value):
    # 处理链表为空的情况
    if head is None:
        return None
    
    # 处理链表头节点为要删除的节点的情况
    while head is not None and head.val == value:
        head = head.next
    
    current = head
    # 遍历链表，找到要删除的节点
    while current is not None and current.next is not None:
        if current.next.val == value:
            current.next = current.next.next
        else:
            current = current.next
    
    return head