我如何从这个承诺中返回数组呢？

function getData() {
  return new Promise((resolve, reject) => {
    // 异步操作，获取数据
    const data = [1, 2, 3, 4, 5];
    resolve(data);
  });
}

getData().then((result) => {
  console.log(result); // 输出数组 [1, 2, 3, 4, 5]
});

import asyncio

async def get_data():
    # 异步操作，获取数据
    data = [1, 2, 3, 4, 5]
    return data

async def main():
    result = await get_data()
    print(result)  # 输出数组 [1, 2, 3, 4, 5]

asyncio.run(main())

import java.util.concurrent.CompletableFuture;

public class Main {
    public static CompletableFuture<Integer[]> getData() {
        return CompletableFuture.supplyAsync(() -> {
            // 异步操作，获取数据
            Integer[] data = {1, 2, 3, 4, 5};
            return data;
        });
    }

    public static void main(String[] args) {
        getData().thenApply(result -> {
            System.out.println(Arrays.toString(result)); // 输出数组 [1, 2, 3, 4, 5]
            return null;
        }).join();
    }
}