有什么方法可以停止pycurl perform()的执行吗？

import pycurl

# 定义回调函数
def callback_func(total_time, total_size, downloaded_size, upload_size, upload_speed):
    # 判断是否需要停止执行
    if should_stop:
        raise pycurl.error(pycurl.E_ABORTED_BY_CALLBACK, "Execution stopped by callback")

# 创建一个Curl对象
c = pycurl.Curl()

# 设置URL
c.setopt(c.URL, "https://example.com")

# 设置回调函数
c.setopt(c.NOPROGRESS, 0)
c.setopt(c.PROGRESSFUNCTION, callback_func)

# 执行请求
try:
    c.perform()
except pycurl.error as e:
    # 捕获中断执行的错误
    if e.args[0] == pycurl.E_ABORTED_BY_CALLBACK:
        print("Execution stopped by callback")
    else:
        print("An error occurred:", e)

# 关闭Curl对象
c.close()