查找列表中所有最大值索引的最快方法-- Python

def find_max_indexes(nums):
    max_value = float('-inf')
    max_indexes = []
    for i in range(len(nums)):
        if nums[i] > max_value:
            max_value = nums[i]
            max_indexes = [i]
        elif nums[i] == max_value:
            max_indexes.append(i)
    return max_indexes

# 示例使用：
numbers = [1, 3, 5, 3, 6, 3, 5]
result = find_max_indexes(numbers)
print(result)  # 输出：[2, 6]

def find_max_indexes(nums):
    max_value = max(nums)
    max_indexes = [i for i, num in enumerate(nums) if num == max_value]
    return max_indexes

# 示例使用：
numbers = [1, 3, 5, 3, 6, 3, 5]
result = find_max_indexes(numbers)
print(result)  # 输出：[2, 6]

import numpy as np

def find_max_indexes(nums):
    arr = np.array(nums)
    max_value = np.max(arr)
    max_indexes = np.argwhere(arr == max_value).flatten().tolist()
    return max_indexes

# 示例使用：
numbers = [1, 3, 5, 3, 6, 3, 5]
result = find_max_indexes(numbers)
print(result)  # 输出：[2, 6]