检查JavaScript中是否有多个不带if语句的cases

function checkCases() {
  const code = "switch (value) {\n" +
               "  case 1:\n" +
               "    // do something\n" +
               "    break;\n" +
               "  case 2:\n" +
               "    if (condition) {\n" +
               "      // do something\n" +
               "    }\n" +
               "    break;\n" +
               "  case 3:\n" +
               "    // do something\n" +
               "    break;\n" +
               "}";

  const regex = /if\s*\(/g;
  let match;
  let hasIfStatement = false;

  while ((match = regex.exec(code)) !== null) {
    hasIfStatement = true;
    break;
  }

  if (hasIfStatement) {
    console.log("存在多个不带if语句的cases");
  } else {
    console.log("不存在多个不带if语句的cases");
  }
}

checkCases();