比较java中两个数据结构的最快方法

int[] arr1 = {1, 2, 3};
int[] arr2 = {1, 2, 3};
boolean isEqual = Arrays.equals(arr1, arr2);
int compareResult = Arrays.compare(arr1, arr2);

List<Integer> list1 = Arrays.asList(1, 2, 3);
List<Integer> list2 = Arrays.asList(1, 2, 3);
Collections.sort(list1);
Collections.sort(list2);
boolean isEqual = list1.equals(list2);

Set<Integer> set1 = new HashSet<>(Arrays.asList(1, 2, 3));
Set<Integer> set2 = new HashSet<>(Arrays.asList(1, 2, 3));
boolean isEqual = set1.equals(set2);

Map<String, Integer> map1 = new HashMap<>();
map1.put("one", 1);
map1.put("two", 2);
map1.put("three", 3);

Map<String, Integer> map2 = new HashMap<>();
map2.put("one", 1);
map2.put("two", 2);
map2.put("three", 3);

boolean isEqual = map1.equals(map2);