用Java程序试图找出有4个因数的数字，但输出错误

public class FindNumberWithFourFactors {
    public static void main(String[] args) {
        int count = 0;
        for (int i = 1; i <= 100; i++) {
            if (getFactorsCount(i) == 4) {
                System.out.println(i);
                count++;
            }
        }
        System.out.println("Total numbers with 4 factors: " + count);
    }

    private static int getFactorsCount(int number) {
        int count = 0;
        for (int i = 1; i <= number; i++) {
            if (number % i == 0) {
                count++;
            }
        }
        return count;
    }
}