用Spring Data REST实现深度嵌套更新JSON结构的最佳方式是什么？

@RestController
@RequestMapping("/api")
public class UserController {

    @Autowired
    private UserRepository userRepository;

    @PatchMapping("/users/{id}")
    public ResponseEntity<?> updateUser(@PathVariable("id") Long id, @RequestBody Map<String, Object> updates) {
        User user = userRepository.findById(id).orElseThrow(() -> new ResourceNotFoundException("User not found with id: " + id));

        applyUpdates(user, updates);

        User updatedUser = userRepository.save(user);

        return ResponseEntity.ok(updatedUser);
    }

    private void applyUpdates(User user, Map<String, Object> updates) {
        for (Map.Entry<String, Object> entry : updates.entrySet()) {
            String field = entry.getKey();
            Object value = entry.getValue();

            if (field.equals("name")) {
                user.setName((String) value);
            } else if (field.equals("address")) {
                Map<String, Object> addressUpdates = (Map<String, Object>) value;
                applyAddressUpdates(user.getAddress(), addressUpdates);
            } else if (field.equals("contacts")) {
                List<Map<String, Object>> contactUpdates = (List<Map<String, Object>>) value;
                applyContactUpdates(user.getContacts(), contactUpdates);
            }
            // Handle other fields as needed
        }
    }

    private void applyAddressUpdates(Address address, Map<String, Object> updates) {
        for (Map.Entry<String, Object> entry : updates.entrySet()) {
            String field = entry.getKey();
            Object value = entry.getValue();

            if (field.equals("street")) {
                address.setStreet((String) value);
            } else if (field.equals("city")) {
                address.setCity((String) value);
            }
            // Handle other fields as needed
        }
    }

    private void applyContactUpdates(List<Contact> contacts, List<Map<String, Object>> updates) {
        // Apply updates to each contact in the list
    }
}