给出任何lat.，long。坐标，在列表中找到最接近的坐标的最快方法是什么？

import math

def calculate_distance(lat1, long1, lat2, long2):
    # 使用Haversine公式计算两个坐标之间的距离
    radius = 6371  # 地球平均半径，单位为公里
    dlat = math.radians(lat2 - lat1)
    dlong = math.radians(long2 - long1)
    a = math.sin(dlat/2) * math.sin(dlat/2) + math.cos(math.radians(lat1)) * math.cos(math.radians(lat2)) * math.sin(dlong/2) * math.sin(dlong/2)
    c = 2 * math.atan2(math.sqrt(a), math.sqrt(1-a))
    distance = radius * c
    return distance

def find_closest_coordinate(coordinates, target_lat, target_long):
    distances = []
    for coordinate in coordinates:
        lat = coordinate['lat']
        long = coordinate['long']
        distance = calculate_distance(target_lat, target_long, lat, long)
        distances.append((coordinate, distance))
    
    distances.sort(key=lambda x: x[1])  # 根据距离排序
    
    closest_coordinate = distances[0][0]  # 最接近的坐标
    return closest_coordinate

# 坐标列表示例
coordinates = [
    {'lat': 40.7128, 'long': -74.0060},
    {'lat': 34.0522, 'long': -118.2437},
    {'lat': 51.5074, 'long': -0.1278},
    # 其他坐标...
]

# 给定的目标坐标
target_lat = 37.7749
target_long = -122.4194

closest_coordinate = find_closest_coordinate(coordinates, target_lat, target_long)
print(closest_coordinate)