运行函数后，如何设置链表的新头部？

class ListNode:
    def __init__(self, val=0, next=None):
        self.val = val
        self.next = next

def setNewHead(node, newVal):
    newHead = ListNode(newVal)  # 创建新的头节点
    newHead.next = node.next    # 将原链表头节点连接到新链表的第二个节点
    node.next = None            # 断开原链表头节点和第二个节点的连接
    node = newHead              # 将新定义的节点作为新的链表头部

# 示例用法
# 假设原链表为 1 -> 2 -> 3 -> 4 -> 5
head = ListNode(1)
node2 = ListNode(2)
node3 = ListNode(3)
node4 = ListNode(4)
node5 = ListNode(5)
head.next = node2
node2.next = node3
node3.next = node4
node4.next = node5

setNewHead(head, 6)  # 将链表的头部设置为新节点 6

# 输出修改后的链表
current = head
while current:
    print(current.val)
    current = current.next

# 输出结果为：6 -> 2 -> 3 -> 4 -> 5