重命名文件夹中的特定文件:仅更改前几个数字

import os

def rename_files(folder_path, prefix_length):
    for filename in os.listdir(folder_path):
        if filename.startswith("file") and filename.endswith(".txt"):
            prefix = filename[:prefix_length]
            new_filename = prefix + filename[prefix_length:]
            os.rename(os.path.join(folder_path, filename), os.path.join(folder_path, new_filename))

# 调用示例
folder_path = "/path/to/folder"  # 文件夹路径
prefix_length = 3  # 前几个数字的长度
rename_files(folder_path, prefix_length)

$folderPath = "C:\path\to\folder"  # 文件夹路径
$prefixLength = 3  # 前几个数字的长度

Get-ChildItem -Path $folderPath -Filter "file*.txt" | ForEach-Object {
    $prefix = $_.Name.Substring(0, $prefixLength)
    $newFilename = $prefix + $_.Name.Substring($prefixLength)
    Rename-Item -Path $_.FullName -NewName $newFilename
}

folderPath="/path/to/folder"  # 文件夹路径
prefixLength=3  # 前几个数字的长度

for file in $folderPath/file*.txt; do
    prefix=$(basename "$file" | cut -c 1-$prefixLength)
    newFilename="$prefix${file##*$prefix}"
    mv "$file" "$folderPath/$newFilename"
done