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python中os.path.isabs(path)的分析

首先,给段资料 The current os.path.isabs documentation says: > isabs(path) >    Return True if path is an absolute pathname (begins with a slash). The "begins with a slash" part is incorrect since certain systems use a different pathname notation. For example, on Macintosh (where os.sep == ":") this is an absolute pathname: hardDriveName:folderName1:folderName2:fileName.ext ...and this is a relative one: :folderName1:fileName.ext Moreover, on Windows os.path.isabs('\\') returns True since '\\' is an alias for the current drive letter (e.g. C:\\) hence, independently from what said before, the documentation should include also the "backslash" term. It turns out that on Windows there are really 4 different kinds of paths: 1) Completely relative, e.g. foo\bar 2) Completely absolute, e.g. c:\foo\bar or \\server\share 3) Halfbreeds with no drive, e.g. \foo\bar 4) Halfbreeds relative to the current working directory on a specific drive, e.g. c:foo\bar Python 2.5's os.path.isabs() method considers both (2) and (3) to be absolute; 然后,分析 |这里第二个应该是相对路径吧? 应该返回False? 根据, linux中absolute *is* begins with a slash, so return True 说说,第三个吧,你除非在"/"目录下,要不然在其他目录下当然是错的,应为这个路径就不对 而,我在"/"目录下也试了,也返回False,那是因为没有以slash开始 linux中,你只用记下上面那句话就好,其他系统看上面的资料

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