Akka Stream Java -是否可以将未知数量的源合并为一个源

import akka.NotUsed;
import akka.actor.ActorSystem;
import akka.stream.ActorMaterializer;
import akka.stream.javadsl.Merge;
import akka.stream.javadsl.Source;

public class MergeExample {
    public static void main(String[] args) {
        // 创建Actor系统和材料化器
        ActorSystem system = ActorSystem.create("MergeExample");
        ActorMaterializer materializer = ActorMaterializer.create(system);

        // 创建三个源
        Source<Integer, NotUsed> source1 = Source.range(1, 5);
        Source<Integer, NotUsed> source2 = Source.range(6, 10);
        Source<Integer, NotUsed> source3 = Source.range(11, 15);

        // 合并三个源为一个源
        Source<Integer, NotUsed> mergedSource = Source.combine(source1, source2, source3, Merge::create);

        // 打印合并后的源的元素
        mergedSource.runForeach(System.out::println, materializer);
    }
}