Flutter :如何从列表中获取其他属性的值？

class Person {
  final String name;
  final int age;

  Person({required this.name, required this.age});
}

List<Person> persons = [
  Person(name: 'John', age: 25),
  Person(name: 'Alice', age: 30),
  Person(name: 'Bob', age: 35),
];

ListView.builder(
  itemCount: persons.length,
  itemBuilder: (BuildContext context, int index) {
    Person person = persons[index];
    String name = person.name;
    int age = person.age;

    // 在这里可以使用name和age属性进行其他操作
    // 例如，将它们显示在列表项中
    return ListTile(
      title: Text(name),
      subtitle: Text('Age: $age'),
    );
  },
);