JAVA中如何在HTTP Put中传递JSON body

import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPut;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONObject;

public class Main {
    public static void main(String[] args) {
        try {
            // 创建HttpClient对象
            HttpClient httpClient = new DefaultHttpClient();

            // 设置请求的URL
            String url = "http://example.com/api/resource";

            // 创建HttpPut对象
            HttpPut httpPut = new HttpPut(url);

            // 创建JSONObject对象并添加数据
            JSONObject json = new JSONObject();
            json.put("key1", "value1");
            json.put("key2", "value2");

            // 将JSONObject对象转换为字符串并设置为HttpPut请求的Entity
            StringEntity entity = new StringEntity(json.toString());
            httpPut.setEntity(entity);

            // 设置请求的Content-Type头部
            httpPut.setHeader("Content-Type", "application/json");

            // 执行HttpPut请求并获取响应
            HttpResponse response = httpClient.execute(httpPut);

            // 解析响应
            int statusCode = response.getStatusLine().getStatusCode();
            String responseBody = EntityUtils.toString(response.getEntity());

            // 处理返回的结果
            System.out.println("Status Code: " + statusCode);
            System.out.println("Response Body: " + responseBody);

            // 关闭HttpClient连接
            httpClient.getConnectionManager().shutdown();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}