Java 8流按最大重复数排序，然后按distinct排序

List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 4, 5, 5, 5);
Stream<Integer> stream = numbers.stream();

Map<Integer, Long> frequencyMap = stream.collect(Collectors.groupingBy(Function.identity(), Collectors.counting()));

List<Map.Entry<Integer, Long>> sortedList = new ArrayList<>(frequencyMap.entrySet());
sortedList.sort(Comparator.comparing(Map.Entry<Integer, Long>::getValue).reversed());

List<Integer> sortedDistinctList = sortedList.stream().map(Map.Entry::getKey).collect(Collectors.toList());

import java.util.*;
import java.util.function.Function;
import java.util.stream.Collectors;
import java.util.stream.Stream;

public class Main {
    public static void main(String[] args) {
        List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 4, 5, 5, 5);
        Stream<Integer> stream = numbers.stream();

        Map<Integer, Long> frequencyMap = stream.collect(Collectors.groupingBy(Function.identity(), Collectors.counting()));

        List<Map.Entry<Integer, Long>> sortedList = new ArrayList<>(frequencyMap.entrySet());
        sortedList.sort(Comparator.comparing(Map.Entry<Integer, Long>::getValue).reversed());

        List<Integer> sortedDistinctList = sortedList.stream().map(Map.Entry::getKey).collect(Collectors.toList());

        System.out.println(sortedDistinctList);
    }
}