Java:在新行的开头匹配重复字符并替换相同数量的备选项

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {
    public static void main(String[] args) {
        String input = "AAABBBCCCDDDEEE";
        String pattern = "(.)\\1*";

        Pattern regex = Pattern.compile(pattern);
        Matcher matcher = regex.matcher(input);

        StringBuffer output = new StringBuffer();
        while (matcher.find()) {
            String match = matcher.group();
            String replacement = getReplacement(match);

            matcher.appendReplacement(output, replacement);
        }
        matcher.appendTail(output);

        System.out.println(output.toString());
    }

    private static String getReplacement(String match) {
        // 根据需要进行替换逻辑的实现
        // 这里只是简单地将匹配到的字符替换为其长度
        return String.valueOf(match.length());
    }
}