JavaScript -比较两个数组并返回两个数组中不存在的数组

function compareArrays(arr1, arr2) {
  const diff1 = arr1.filter(item => !arr2.includes(item));
  const diff2 = arr2.filter(item => !arr1.includes(item));
  return [...diff1, ...diff2];
}

const array1 = [1, 2, 3, 4, 5];
const array2 = [3, 4, 5, 6, 7];
const result = compareArrays(array1, array2);
console.log(result); // [1, 2, 6, 7]

function compareArrays(arr1, arr2) {
  const diff = arr1.reduce((result, item) => {
    if (!arr2.includes(item)) {
      result.push(item);
    }
    return result;
  }, []);
  return diff;
}

const array1 = [1, 2, 3, 4, 5];
const array2 = [3, 4, 5, 6, 7];
const result = compareArrays(array1, array2);
console.log(result); // [1, 2, 6, 7]

function compareArrays(arr1, arr2) {
  const set1 = new Set(arr1);
  const set2 = new Set(arr2);
  const diff = [...arr1.filter(item => !set2.has(item)), ...arr2.filter(item => !set1.has(item))];
  return diff;
}

const array1 = [1, 2, 3, 4, 5];
const array2 = [3, 4, 5, 6, 7];
const result = compareArrays(array1, array2);
console.log(result); // [1, 2, 6, 7]